10.4. An Introduction to Analysis of
Variance
Analysis of Variance
(ANOVA): a statistical technique can be used to test
the hypothesis that the means of 3 or more populations
are equal.
General Case:
Suppose
there are K populations. The data are the following
|
Populations |
Samples |
|
1 |
|
|
2 |
|
|
|
|
|
k |
|
3 assumptions for the above problem:
1.
Normal populations.
2.
Equal variance for all populations.
3. The
data must be independent of any other one.
Let
![]()
: the i’th sample value form population k.
: the sample mean for population j.
the overall mean.
: the sample variance for population j.
: F distribution with degrees of
and
.
F test:
Let
vs. ![]()
Then,
,
where
,
can be obtained
by
,
MSB=Mean
Square Between, and
MSW=Mean
Square Within.
In
addition,
![]()
Example 5:
Five observations were
selected from each of three populations. The data obtained follow.
|
Observation |
Sample 1 |
Sample 2 |
Sample 3 |
|
1 |
32 |
44 |
33 |
|
2 |
30 |
43 |
36 |
|
3 |
30 |
44 |
35 |
|
4 |
26 |
46 |
36 |
|
5 |
32 |
48 |
40 |
|
Sample mean |
30 |
45 |
36 |
|
Sample variance |
6 |
4 |
6.5 |
(i)
Set up the ANOVA table for this problem.
(ii) At the
level of
significance, test the null hypothesis that
the three population means are equal?
[solution:]

Therefore,
|
Source |
DF |
SS |
MS |
F |
|
Between |
2 |
570 |
285 |
51.82 |
|
Within |
12 |
66 |
5.5 |
|
|
Total |
14 |
636 |
|
|
(ii)
.
JavaStatSoft:
F
test:
Statistics
-> Tests -> One-Way ANOVA